You are trying to assign the result to ADODB.Recordset Change the rs2 definition to dim rs2 as DAO.Recordset share|improve this answer answered Nov 28 '08 at 9:50 shahkalpesh 26.2k23976 add a Thanks. –Mike Apr 9 '15 at 15:47 None of your VBA seems to be built events from the forms. Sıradaki VBA Run-Time Error '13' Type Mismatch - Süre: 2:18. In which case you need to have txtUserName.value either that or it is a variable in the code. his comment is here
How do I politely decline a research grant? Order of operations in statistics Can an NPC healer be part of a party of PCs, and if so, how does that work? Why are terminal consoles still used? To print arrays, create a loop that displays each element individually. For additional information, select the item in question and press F1. https://msdn.microsoft.com/en-us/library/aa264979(v=vs.60).aspx
I actually reselected the type from the list just to make sure Access was sure about what was selected. Disabling on-the-fly projecting in Arcmap? Are there any OSes that verify program signatures before executing them? Oturum aç 10 9 Bu videoyu beğenmediniz mi?
Text Quote Post |Replace Attachment Add link Text to display: Where should this link go? Making a Planet Seem Uninhabitable Does Blender have a histogram? Seems there are now going to be some compatibility issues with some of the Access 2007 code that's not compatible with Access 2013. Run Time Error 13 Type Mismatch Excel 2013 Views Block Question If something is neither true nor false, what is it?
asked 4 years ago viewed 6679 times active 4 years ago Related 0Using an If statement, produces runtime-13 type mismatch error0Using VBA Runtime error 13 'type mismatch' while assigning a modified Runtime Error 13 Type Mismatch Fix It opens the Excel workbook, then cycles through the Access subforms and transfers data. WiseOwlTutorials 81.364 görüntüleme 1:39:07 Sistema de Pedidos Excel/VBA - Parte 11 - Süre: 10:00. tacjoe fan 1.322 görüntüleme 1:15 How to debug Excel VBA - Süre: 5:50.
When a text box in Calendar is clicked, it opens frmMagnet and is supposed to call a function declared in frmMagnet. Type Mismatch Error In Vbscript DAO, ADODB or something. 0 This discussion has been inactive for over a year. Prove that odd polynomials have at least one root. I am guessing it would be that txtusername is the name of a text box.
aadel115 28.251 görüntüleme 2:08 How to Install Microsoft Access 2002 Runtime - Süre: 0:44.
Oturum aç İstatistikler 24.658 görüntüleme 9 Bu videoyu beğendiniz mi? Run Time Error 13 Type Mismatch Excel Thank you for pointing out how to turn this on. Runtime Error 13 Type Mismatch Vb6 Also I added some onto the textbox name so it grabs it even if the form is not selected.
though, I have never seen that. this content EverydayVBA 14.361 görüntüleme 4:04 Error Handling Excel VBA - Süre: 9:43. THANK YOU!!! Kapat Daha fazla bilgi edinin View this message in English YouTube 'u şu dilde görüntülüyorsunuz: Türkçe. Compile Error Type Mismatch Vba
Join them; it only takes a minute: Sign up MS Access VBA: Getting Error '13': Type Mismatch when calling a function from a different form up vote 1 down vote favorite In the VBA IDE, go under the Tools Menu, select Options and then select the General tab. How to generate all string's suffixes after split? weblink Thanks vba runtime runtime-error share|improve this question edited Aug 21 '13 at 21:15 alfasin 33.6k73874 asked Aug 21 '13 at 21:11 ELS31987 5128 add a comment| 2 Answers 2 active oldest
Also, be sure that the form is open. Runtime Error 13 Type Mismatch Excel 2007 This documentation is archived and is not being maintained. Yükleniyor... Çalışıyor...
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I get the same error Set rstLogin = CurrentDb().OpenRecordset("Select * from tbl_Login where IsValid = yes And UserName = '" & txtUserName.Value & "'", dbOpenDynaset, dbSeeChanges) Ok when it comes to VBA You may get a better answer to your question by starting a new discussion. vba ms-access-2013 type-mismatch share|improve this question edited Apr 13 '15 at 2:51 asked Apr 9 '15 at 15:27 Mike 160114 Please include CalenderArray method implementation. –PaulFrancis Apr 9 '15 IsValid needs to be yes/no. 0 Sonora OP Kelvin8694 May 2, 2014 at 5:50 UTC Thanks for the reply!
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